Mathematical Aptitude | Percentages Aptitude Questions with Answer for Placement

Mathematical aptitude is a key component of placement exams, especially when it comes to mastering percentage-based questions. Understanding percentages is crucial for solving a variety of problems that frequently appear in competitive tests and job placements. In this guide, we'll explore essential percentage aptitude questions along with their detailed answers to help you build your skills and boost your confidence. 

Whether you’re preparing for placement tests or simply looking to improve your mathematical aptitude, this resource provides practical exercises and solutions to enhance your problem-solving abilities.

Mathematical Aptitude | Percentages Aptitude Questions with Answer for Placement

Percentages Aptitude Questions For Placement Jobs

1. Rohan spends 60% of his salary. If he saves ₹18,000, what is his total salary?

1. ₹45,000
2. ₹30,000
3. ₹36,000
4. ₹40,000

Solution

Answer: ₹45,000.

Saves 40% of salary = ₹18,000.

Total Salary = (18,000 x 0.40) = ₹45,000.

40% can be written as:

0.40 (in decimal form)

$\frac{30}{100}$ (as a fraction)

40 out of 100 (as a ratio)

2. The population of a town is 20,000. It decreases annually at the rate of 10%. What will be its population after 2 years?

1. ₹15,200
2. ₹16,200
3. ₹16,000
4. ₹10,200

Solution

Answer: ₹16,200.

The population decreases by 10% each year. The formula for population after𝑛 n years is: 

Population=P×(1−r)^n

where P = 20,000, r = 0.10, and 𝑛 = 2 :

Population = 20,000×(1−0.10)^2

Population = 20,000×0.81 = ₹16,200.

3. A man bought a car at 75% of its marked price. He sold it for 80% of the marked price, thus making a profit of ₹10,000. What is the marked price of the car?

1. ₹10,00,00
2. ₹16,00,20
3. ₹19,00,00
4. ₹20,00,00

Solution

Answer: ₹20,00,00.

Let the marked price be M.
Cost price = 75% of M: ( 0.75M)
Selling price = 80% of M: (0.85M)
Profit = selling price - cost price:
0.80M − 0.75M = 0.05M
Given that the Profit is ₹10,000:
0.05M = 10,000
M =0.05/10,00 = ₹20,00,00.

4. A shirt is marked at ₹800 and is sold with a 25% discount. What is the selling price?

1. ₹600
2. ₹650
3. ₹575
4. ₹720

Solution

Answer: ₹600.

Marked price = ₹800
Discount = 25%
Selling price = ₹800 - (25% of ₹800)
Selling price = ₹800 - ₹200 = ₹600

5. A student scored 70% on a test. If the total marks are 200, how many marks did the student score?

1. 140
2. 150
3. 160
4. 170

Solution

Answer: 140.

Total marks = 200
Marks scored = 70% of 200
Marks scored = 0.70 × 200 = 140

6. The price of a book increased by 15% to ₹115. What was the original price?

1. ₹100
2. ₹95
3. ₹90
4. ₹105

Solution

Answer: ₹100.

New price = ₹115
Increase = 15%
Original price = ₹115 / 1.15 = ₹100

7. If a product originally costs ₹150 and is now reduced by 10%, what is the new price?

1. ₹135
2. ₹140
3. ₹125
4. ₹145

Solution

Answer: ₹135.

Original price = ₹150
Discount = 10%
New price = ₹150 - (10% of ₹150)
New price = ₹150 - ₹15 = ₹135

8. A jacket costs ₹500 after a 20% discount. What was the marked price?

1. ₹600
2. ₹625
3. ₹650
4. ₹700

Solution

Answer: ₹625.

Selling price = ₹500
Discount = 20%
Marked price = ₹500 / 0.80 = ₹625

9. If 40% of a number is 60, what is the number?

1. 150
2. 200
3. 180
4. 240

Solution

Answer: 150.

40% of the number = 60
Number = 60 / 0.40 = 150

10. A company’s profit increased by 30% to ₹65,000. What was the original profit?

1. ₹50,000
2. ₹45,000
3. ₹48,000
4. ₹55,000

Solution

Answer: ₹50,000.

New profit = ₹65,000
Increase = 30%
Original profit = ₹65,000 / 1.30 = ₹50,000

11. An item is sold for ₹90 after a 10% discount. What is the marked price?

1. ₹100
2. ₹110
3. ₹95
4. ₹105

Solution

Answer: ₹100.

Selling price = ₹90
Discount = 10%
Marked price = ₹90 / 0.90 = ₹100

12. If a person’s salary increases from ₹30,000 to ₹36,000, what is the percentage increase in salary?

1. 15%
2. 20%
3. 25%
4. 30%

Solution

Answer: 20%.

Old salary = ₹30,000
New salary = ₹36,000
Percentage increase = (₹36,000 - ₹30,000) / ₹30,000 × 100 = 20%

13. The value of a car depreciated by 12% to ₹88,000. What was the original value of the car?

1. ₹100,000
2. ₹95,000
3. ₹90,000
4. ₹85,000

Solution

Answer: ₹100,000.

Depreciated value = ₹88,000
Depreciation = 12%
Original value = ₹88,000 / 0.88 = ₹100,000